std::count, std::count_if
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Defined in header <algorithm>
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template< class InputIt, class T > typename iterator_traits<InputIt>::difference_type |
(1) | |
template< class InputIt, class UnaryPredicate > typename iterator_traits<InputIt>::difference_type |
(2) | |
Retourne le nombre d'éléments dans la gamme
[first, last)
satisfaisant des critères spécifiques. La première version compte les éléments qui sont égaux à value
, la deuxième version compte les éléments pour lesquels prédicat retourne p
true . Original:
Returns the number of elements in the range
[first, last)
satisfying specific criteria. The first version counts the elements that are equal to value
, the second version counts elements for which predicate p
returns true. The text has been machine-translated via Google Translate.
You can help to correct and verify the translation. Click here for instructions.
You can help to correct and verify the translation. Click here for instructions.
Sommaire |
[modifier] Paramètres
first, last | - | l'éventail des éléments à examiner
Original: the range of elements to examine The text has been machine-translated via Google Translate. You can help to correct and verify the translation. Click here for instructions. |
value | - | la valeur à rechercher
Original: the value to search for The text has been machine-translated via Google Translate. You can help to correct and verify the translation. Click here for instructions. |
p | - | unary predicate which returns true pour les éléments requis . Original: for the required elements The text has been machine-translated via Google Translate. You can help to correct and verify the translation. Click here for instructions. The signature of the predicate function should be equivalent to the following: bool pred(const Type &a); The signature does not need to have const &, but the function must not modify the objects passed to it. |
Type requirements | ||
-InputIt must meet the requirements of InputIterator .
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[modifier] Retourne la valeur
certain nombre d'éléments satisfaisant la condition .
Original:
number of elements satisfying the condition.
The text has been machine-translated via Google Translate.
You can help to correct and verify the translation. Click here for instructions.
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[modifier] Complexité
exactement
last
- first
comparaisons / applications du prédicatOriginal:
exactly
last
- first
comparisons / applications of the predicateThe text has been machine-translated via Google Translate.
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[modifier] Mise en œuvre possible
First version |
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template<class InputIt, class T> typename iterator_traits<InputIt>::difference_type count(InputIt first, InputIt last, const T& value) { typename iterator_traits<InputIt>::difference_type ret = 0; for (; first != last; ++first) { if (*first == value) { ret++; } } return ret; } |
Second version |
template<class InputIt, class UnaryPredicate> typename iterator_traits<InputIt>::difference_type count_if(InputIt first, InputIt last, UnaryPredicate p) { typename iterator_traits<InputIt>::difference_type ret = 0; for (; first != last; ++first) { if (p(*first)) { ret++; } } return ret; } |
[modifier] Exemple
Au code
count
utilise pour déterminer le nombre de nombres entiers dans un std::vector correspond à une valeur cible .
Original:
The following code uses
count
to determine how many integers in a std::vector match a target value.
The text has been machine-translated via Google Translate.
You can help to correct and verify the translation. Click here for instructions.
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#include <algorithm> #include <iostream> #include <vector> int main() { int data[] = { 1, 2, 3, 4, 4, 3, 7, 8, 9, 10 }; std::vector<int> v(data, data+10); int target1 = 3; int target2 = 5; int num_items1 = std::count(v.begin(), v.end(), target1); int num_items2 = std::count(v.begin(), v.end(), target2); std::cout << "number: " << target1 << " count: " << num_items1 << '\n'; std::cout << "number: " << target2 << " count: " << num_items2 << '\n'; }
Résultat :
number: 3 count: 2 number: 5 count: 0
Cet exemple utilise un expression lambda de compter des éléments divisible par 3 .
Original:
This example uses a expression lambda to count elements divisible by 3.
The text has been machine-translated via Google Translate.
You can help to correct and verify the translation. Click here for instructions.
You can help to correct and verify the translation. Click here for instructions.
#include <algorithm> #include <iostream> #include <vector> int main() { int data[] = { 1, 2, 3, 4, 4, 3, 7, 8, 9, 10 }; std::vector<int> v(data, data+10); int num_items1 = std::count_if(v.begin(), v.end(), [](int i) {return i % 3 == 0;}); std::cout << "number divisible by three: " << num_items1 << '\n'; }
Résultat :
number divisible by three: 3