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algorithm

Merge Sort

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Examples

  • 6

    Merge Sort is a divide-and-conquer algorithm. It divides the input list of length n in half successively until there are n lists of size 1. Then, pairs of lists are merged together with the smaller first element among the pair of lists being added in each step. Through successive merging and through comparison of first elements, the sorted list is built.

    An example:

    Merge Sort example

    Time Complexity: T(n) = 2T(n/2) + Θ(n)

    The above recurrence can be solved either using Recurrence Tree method or Master method. It falls in case II of Master Method and solution of the recurrence is Θ(nLogn). Time complexity of Merge Sort is Θ(nLogn) in all 3 cases (worst, average and best) as merge sort always divides the array in two halves and take linear time to merge two halves.

    Auxiliary Space: O(n)

    Algorithmic Paradigm: Divide and Conquer

    Sorting In Place: Not in a typical implementation

    Stable: Yes

  • 1
    package main
    
    import "fmt"
    
    func mergeSort(a []int) []int {
        if len(a) < 2 {
            return a
        }
        m := (len(a)) / 2
    
        f := mergeSort(a[:m])
        s := mergeSort(a[m:])
    
        return merge(f, s)
    }
    
    func merge(f []int, s []int) []int {
        var i, j int
        size := len(f) + len(s)
    
        a := make([]int, size, size)
    
        for z := 0; z < size; z++ {
            lenF := len(f)
            lenS := len(s)
    
            if i > lenF-1 && j <= lenS-1 {
                a[z] = s[j]
                j++
            } else if j > lenS-1 && i <= lenF-1 {
                a[z] = f[i]
                i++
            } else if f[i] < s[j] {
                a[z] = f[i]
                i++
            } else {
                a[z] = s[j]
                j++
            }
        }
    
        return a
    }
    
    func main() {
        a := []int{75, 12, 34, 45, 0, 123, 32, 56, 32, 99, 123, 11, 86, 33}
        fmt.Println(a)
        fmt.Println(mergeSort(a))
    }
    
  • 0
    public class MergeSortBU {
        private static Integer[] array = { 4, 3, 1, 8, 9, 15, 20, 2, 5, 6, 30, 70, 60,80,0,9,67,54,51,52,24,54,7 };
    
        public MergeSortBU() {
        }
    
        private static void merge(Comparable[] arrayToSort, Comparable[] aux, int lo,int mid, int hi) {
    
            for (int index = 0; index < arrayToSort.length; index++) {
                aux[index] = arrayToSort[index];
            }
    
            int i = lo;
            int j = mid + 1;
            for (int k = lo; k <= hi; k++) {
                if (i > mid)
                    arrayToSort[k] = aux[j++];
                else if (j > hi)
                    arrayToSort[k] = aux[i++];
                else if (isLess(aux[i], aux[j])) {
                    arrayToSort[k] = aux[i++];
                } else {
                    arrayToSort[k] = aux[j++];
                }
    
            }
        }
    
        public static void sort(Comparable[] arrayToSort, Comparable[] aux, int lo, int hi) {
            int N = arrayToSort.length;
            for (int sz = 1; sz < N; sz = sz + sz) {
                for (int low = 0; low < N; low = low + sz + sz) {
                    System.out.println("Size:"+ sz);
                    merge(arrayToSort, aux, low, low + sz -1 ,Math.min(low + sz + sz - 1, N - 1));
                    print(arrayToSort);
                }
            }
    
        }
    
        public static boolean isLess(Comparable a, Comparable b) {
            return a.compareTo(b) <= 0;
        }
    
        private static void print(Comparable[] array) {http://stackoverflow.com/documentation/algorithm/5732/merge-sort#
            StringBuffer buffer = new StringBuffer();http://stackoverflow.com/documentation/algorithm/5732/merge-sort#
            for (Comparable value : array) {
                buffer.append(value);
                buffer.append(' ');
            }
            System.out.println(buffer);
        }
    
        public static void main(String[] args) {
            Comparable[] aux = new Comparable[array.length];
            print(array);
            MergeSortBU.sort(array, aux, 0, array.length - 1);
        }
    }
    
  • 0

    C Merge Sort

    int merge(int arr[],int l,int m,int h)
    {
      int arr1[10],arr2[10];  // Two temporary arrays to
      hold the two arrays to be merged
      int n1,n2,i,j,k;
      n1=m-l+1;
      n2=h-m;
    
      for(i=0; i<n1; i++)
        arr1[i]=arr[l+i];
      for(j=0; j<n2; j++)
        arr2[j]=arr[m+j+1];
    
      arr1[i]=9999;  // To mark the end of each temporary array
      arr2[j]=9999;
    
      i=0;
      j=0;
      for(k=l; k<=h; k++) { //process of combining two sorted arrays
        if(arr1[i]<=arr2[j])
          arr[k]=arr1[i++];
        else
          arr[k]=arr2[j++];
      }
    
      return 0;
    }
    
    int merge_sort(int arr[],int low,int high)
    {
      int mid;
      if(low<high) {
        mid=(low+high)/2;
        // Divide and Conquer
        merge_sort(arr,low,mid);
        merge_sort(arr,mid+1,high);
        // Combine
        merge(arr,low,mid,high);
      }
    
      return 0;
    }
    

    C# Merge Sort

    public class MergeSort
        {
            static void Merge(int[] input, int l, int m, int r)
            {
                int i, j;
                var n1 = m - l + 1;
                var n2 = r - m;
    
                var left = new int[n1];
                var right = new int[n2];
    
                for (i = 0; i < n1; i++)
                {
                    left[i] = input[l + i];
                }
    
                for (j = 0; j < n2; j++)
                {
                    right[j] = input[m + j + 1];
                }
    
                i = 0;
                j = 0;
                var k = l;
    
                while (i < n1 && j < n2)
                {
                    if (left[i] <= right[j])
                    {
                        input[k] = left[i];
                        i++;
                    }
                    else
                    {
                        input[k] = right[j];
                        j++;
                    }
                    k++;
                }
    
                while (i < n1)
                {
                    input[k] = left[i];
                    i++;
                    k++;
                }
    
                while (j < n2)
                {
                    input[k] = right[j];
                    j++;
                    k++;
                }
            }
    
            static void SortMerge(int[] input, int l, int r)
            {
                if (l < r)
                {
                    int m = l + (r - l) / 2;
                    SortMerge(input, l, m);
                    SortMerge(input, m + 1, r);
                    Merge(input, l, m, r);
                }
            }
    
            public static int[] Main(int[] input)
            {
                SortMerge(input, 0, input.Length - 1);
                return input;
            }
        }
    
  • 0

    Below there is the implementation in Java using a generics approach. It is the same algorithm, which is presented above.

    public interface InPlaceSort<T extends Comparable<T>> {
    void sort(final T[] elements); }
    
    
    public class MergeSort < T extends Comparable < T >> implements InPlaceSort < T > {
    
    
    @Override
    public void sort(T[] elements) {
        T[] arr = (T[]) new Comparable[elements.length];
        sort(elements, arr, 0, elements.length - 1);
    }
    
    // We check both our sides and then merge them
    private void sort(T[] elements, T[] arr, int low, int high) {
        if (low >= high) return;
        int mid = low + (high - low) / 2;
        sort(elements, arr, low, mid);
        sort(elements, arr, mid + 1, high);
        merge(elements, arr, low, high, mid);
    }
    
    
    private void merge(T[] a, T[] b, int low, int high, int mid) {
        int i = low;
        int j = mid + 1;
    
        // We select the smallest element of the two. And then we put it into b
        for (int k = low; k <= high; k++) {
    
            if (i <= mid && j <= high) {
                if (a[i].compareTo(a[j]) >= 0) {
                    b[k] = a[j++];
                } else {
                    b[k] = a[i++];
                }
            } else if (j > high && i <= mid) {
                b[k] = a[i++];
            } else if (i > mid && j <= high) {
                b[k] = a[j++];
            }
        }
    
        for (int n = low; n <= high; n++) {
            a[n] = b[n];
        }}}
    
  • 0
    def merge(X, Y):
        " merge two sorted lists "
        p1 = p2 = 0
        out = []
        while p1 < len(X) and p2 < len(Y):
            if X[p1] < Y[p2]:
                out.append(X[p1])
                p1 += 1
            else:
                out.append(Y[p2])
                p2 += 1
        out += X[p1:] + Y[p2:]
        return out
    
    def mergeSort(A):
        if len(A) <= 1:
            return A
        if len(A) == 2:
            return sorted(A)
    
        mid = len(A) / 2
        return merge(mergeSort(A[:mid]), mergeSort(A[mid:]))
    
    if __name__ == "__main__":
        # Generate 20 random numbers and sort them
        A = [randint(1, 100) for i in xrange(20)]
        print mergeSort(A)
    
    
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Syntax

Syntax

Parameters

Parameters

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Remarks

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