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1

I have a array which has string and array.

I am trying to get the all the values with foreach but it does not work. It seems simple but I am stuck with this. If anybody can tell me where to fix, that would be very great. Thank you in advance.

<?php

$shirts = array();

$shirts[101] = array(
    "size"  =>  "Large",
    "img" =>  array("images/nike1.jpg","images/nike2.jpg","images/nike3.jpg"),
    "price" => "$30";
);

$shirts[102] = array(
    "size"  =>  "Small",
    "img" =>  array("images/adidas1.jpg","images/adidas2.jpg","images/adidas3.jpg"),
    "price" => "$30";
);

$shirts[103] = array(
    "size"  =>  "Medium",
    "img" =>  array("images/puma1.jpg","images/puma2.jpg","images/puma3.jpg"),
    "price" => "$30";
);

$last = count($shirts) - 1;

foreach ($shirts as $i => $row){
    $isFirst = ($i == 0);
    $isLast = ($i == $last);

    if (is_array($row)){
        $lastChild = count($row) - 1;                       
        foreach ($row as $j =>$rowChild){
            $isFirstChild = ($j == 0);
            $isLastChild = ($j == $lastChild);                          

            echo  $rowChild;    

        }
    }else{
            echo  $row;

    }
}

?>
share|improve this question
    
I am trying to get the all the values what do you want at the end? –  Cheery Oct 21 at 4:17
    
What does "does not work" mean in this context? What's the behavior you're trying to correct? –  Jon Kiparsky Oct 21 at 4:18
    
I want to display all the values of the each array. –  user3011308 Oct 21 at 4:18
    
And what is happening that you don't want to have happen? Tell us what problem you want fixed, and you're likely to get a better answer –  Jon Kiparsky Oct 21 at 4:20
    
I can get display the strings in the array but cannot be shown the array. –  user3011308 Oct 21 at 4:21

4 Answers 4

up vote 0 down vote accepted

Your foreach loop should be like this:

foreach( $shirts as $i=>$row ){

    foreach( $row as $j=>$product ){

        if( is_array( $product ) ){
            foreach( $product as $p ){
                echo $p.'<br>';
            }
        } else {
            echo $product.'<br>';
        }

    }

}
share|improve this answer
up vote 1 down vote

I believe the problem lies in this line

foreach ($row as $j =>$rowChild){

since the array inside of the "img" key is not a key value pair, this line will fail. What you want is:

foreach ($row as $rowChild){
share|improve this answer
up vote 1 down vote

In your code, $row stands for:

array(
  "size"  =>  "Large",
  "img" =>  array("images/nike1.jpg","images/nike2.jpg","images/nike3.jpg"),
  "price" => "$30";
)

So $rowChild stands for "Large", array("images/nike1.jpg","images/nike2.jpg","images/nike3.jpg") and "$30" in the loop. And in your second loop, $j is not int index but string index ("size", "img" and "price").

When you try to print the array, it breaks.

share|improve this answer
    
Thank you for kindly helping me to underdstand. –  user3011308 Oct 21 at 4:51
up vote 0 down vote

If you're getting an array to string conversion error, I would look at the line where that error is likely to be triggered:

  echo  $rowChild;

If $rowChild is an array, echoing it isn't going to work. For example, if it's an array of image filenames

share|improve this answer

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