up vote 1 down vote favorite

I'm trying to take the following string that I got as a json object: 

 [
    {
        "id": "picture1",
        "caption": "sample caption",
        "picname": "sample picture name"
      }
 ]

and turn it into a array so I can populate a list

I've tried turning it into a jsonarray by doing this: 

JSONArray myjsonarray = myjson.toJSONArray(string_containing_json_above);

but that didn't seem to work.

==============

Here is full code with the working solution

myjson = new JSONObject(temp);
String String_that_should_be_array = myjson.getString("piclist");
JSONArray myjsonarray = new JSONArray(String_that_should_be_array);
For(int i = 0; i < myjsonarray.length(); i++){
    JSONObject tempJSONobj = myjsonarray.getJSONObject(i);
    showToast(tempJSONobj.get("caption").toString());
}

temp is the json from the server

share|improve this question
    
What is myson? And what is temparray? Have you looked at the JavaDoc for JSONArray? Take note of the constructor that accepts a string. – Perception Apr 11 '13 at 6:12
    
I edited the post to make more sense. I'm sorry. temparray is a string but i've renamed the variable in my code because it was a terrible variable name – TheMcMurder Apr 11 '13 at 6:23
    
Ok, so that clears some stuff up. But you didn't mention what 'myjson' is. But, see answer from @PareshMayani. – Perception Apr 11 '13 at 6:26
up vote 2 down vote accepted

here you get JSONArray so change

JSONArray myjsonarray = myjson.toJSONArray(temparray);

line as shown below

JSONArray jsonArray = new JSONArray(readlocationFeed);

and after

 JSONArray jsonArray =  new JSONArray(readlocationFeed);

    for (int i = 0; i < jsonArray.length(); i++) {
        JSONObject explrObject = jsonArray.getJSONObject(i);
        explrObject.getString("caption");
}
share|improve this answer
    
Perfect!!! Thank you that worked wonderfully. – TheMcMurder Apr 11 '13 at 6:27
    
WC :)......,,,, – kyogs Apr 11 '13 at 6:31
up vote 3 down vote

Issue is here:

JSONArray myjsonarray = myjson.toJSONArray(temparray);

Solution:

JSONArray myjsonarray = new JSONArray(myJSON);   
// myJSON is String

Now here you are having JSONArray, iterate over it and prepare ArrayList of whatever types of you want.

share|improve this answer
    
Sorry I can only mark one as correct but this is correct too. Thank you Paresh Mayani! – TheMcMurder Apr 11 '13 at 6:28
    
I would upvote you but I don't have the reputation to upvote yet. When I do I will. Thank you again. – TheMcMurder Apr 11 '13 at 6:38
up vote 0 down vote

JSONArray isn't working because the JSON you provided is not an array. You can read more about JSON syntax here: http://www.w3schools.com/json/json_syntax.asp

In the meantime, you could manually create your array by paring the JSON one string at a time.

JSONObject strings = new JSONObject(jsonString);
String array[] = new String[5];

if (jsonString.has("id"){
    array[0] = jsonString.getString("id");
}
if (jsonString.has("caption"){
    array[1] = jsonString.getString("caption");
}
...

etc.

share|improve this answer
    
Do you really prefer String[] over ArrayList<String>? – Paresh Mayani Apr 11 '13 at 6:19
    
No, I guess I just thought that since the question specified an "array" that that was what s/he wanted. – dckuehn Apr 11 '13 at 16:49

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