var a = [ { id:1}, {id:2} ];
var b = {id:1};
var res = a.indexOf(b._id) == -1;
console.log(res);
I want to check if b._id
is in a[]
.
Note: a[]
is an array of objects
A better way is using .find
function.
let a = [{
id: 1
}, {
id: 2
}],
b = {
id: 1
},
obj = a.find(function(itm) {
return itm.id == b.id;
});
console.log(obj)
And also using .findIndex
function to get just index of item in array.
let a = [{
id: 1
}, {
id: 2
}],
b = {
id: 1
},
objIndex = a.findIndex(function(itm) {
return itm.id == b.id;
});
console.log(objIndex)
And for getting all objects with that condition use .filter
function.
let a = [{
id: 1
}, {
id: 2
}],
b = {
id: 1
},
objArr = a.filter(function(itm) {
return itm.id == b.id;
});
console.log(objArr)
Use Array.map() function of JavaScript to check it. It will compare id
and its value
as well.
Below is working code:
var a = [{
id: 1
}, {
id: 2
}];
var b = {
id: 1
};
if (a.map(x => x.id).indexOf(b.id) != -1) {
console.log("Available");
} else {
console.log("Not available");
}
You can use Filter of AngularJS
var a = [{id:1}, {id:2}];
var b = {id:1};
var found = false;
var filterResult = $filter('filter')(a, {id: b.id}, true);
if (filterResult.length > 0) {
found = true;
}
a.map(x => x.id).indexOf(b.id) != -1