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up vote 0 down vote favorite

I have a array of objects. the object contains:
code
name.

example: 

var fullList = [
      {"code":10,"name":"example 10"},
      {"code":50,"name":"example 50"},
      {"code":60,"name":"example 60"}
   ]

I have another array with only code, like: 

var filterBy = [10, 50]

I want to create 2 new array:
First - contains only objects that their code in "filterBy"
Second - contains only objects that their code not (!) in "filterBy"

how can i do it?

Thank you

share|improve this question
up vote 1 down vote accepted

Just pass in a function as the filter expression

<div ng-repeat="a in fullList | filter: myFilterBy">
  {{ a }}
</div>

and then

$scope.myFilterBy = function(e) {
  return filterBy.indexOf(e.code) !== -1;
}

Fiddle - https://jsfiddle.net/7tda0bbL/

share|improve this answer
    
wow! perfect and elegant solution...! Thank-you! – prog_prog Mar 27 '16 at 12:45
up vote 0 down vote

You can create 2 arrays as follows -

var arr1 = [];
var arr2 = [];
angular.forEach(fullList, function(obj, key) {
    var indx = filterArray(obj);
    if (indx > -1) {
      arr1.push(obj);
    } else {
      arr2.push(obj);
    }
});
console.log(arr1);
console.log(arr2);

function filterArray(arrObj) {
    return [10, 50].indexOf(arrObj.code);
};
share|improve this answer

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