Tell me more ×
Stack Overflow is a question and answer site for professional and enthusiast programmers. It's 100% free, no registration required.
up vote 2 down vote favorite

i am wounding if i can do this, as i am trying this from last 2 days but no success.

i want to run java script function from php

like

php example

<div id="meprocess"></div>
<?php
for($i=1;$i<=10;$i++)
{
?>
<script>
jfun(<?php echo $i;?>);
</script>
<?php
}
?>

java script

<script type="text/javascript">

function jfun(n)
{
html="Loop is on" + n;
$("<div>"+ html +"</div>").appendTo("div#meprocess");   
}
</script>

i am trying to generate a page which print loop number one by one....

but i got error jfun is not defined.

what i can understand my be java script function is not ready at the time of php execution. is there any way round, like running the php loop when DOM/Page is ready so that java script function will be ready that time, or any other way round....

Thanks

share|improve this question

4 Answers

up vote 1 down vote accepted

You have to define that function before calling it

http://sandbox.phpcode.eu/g/15b02.php

<div id="meprocess"></div>
<script type="text/javascript">

function jfun(n)
{
html="Loop is on" + n;
$("<div>"+ html +"</div>").appendTo("div#meprocess");   
}
<?php
for($i=1;$i<=10;$i++)
{
?>
jfun(<?php echo $i;?>);
<?php
}
?>
</script>
share|improve this answer
up vote 2 down vote

Your PHP code is generating (in a very bad way..) some javascript code that will be executed by the script. Although it should work, this is definitely not the best way to do that - you should run the loop on the js-side, eventually passing values from your PHP script..

However:

The "undefined function" problem is given since you try to run the code before the function is created; using jQuery, to make some code executed only after everything is loaded, use:

$(document).ready(function(){
// Your code here..
})

or just

$(function(){
// Your code here..
})

As described here: http://api.jquery.com/ready/

For the for loop, you should generate some js like this:

<div id="meprocess"></div>
<script type="text/javascript">
for (i=1; i<=10; i++) {
jfun(i);
}
</script>

..maybe, generating the min/max values from the PHP script:

<?php
  $min = 1;
  $max = 10;
?>
<div id="meprocess"></div>
<script type="text/javascript">
for (i=<?php print $min; ?>; i<=<?php print $max; ?>; i++) {
jfun(i);
}
</script>

..that's more good practice than writing N function calls in order to loop..

share|improve this answer
Also, remember to have the jQuery loaded before executing that code, or you'll have the same problem since $ (aka jQuery) has not been defined yet. – redShadow Jul 31 '11 at 21:44
up vote 0 down vote

First of all, ensure that your javascript function is above function uses.

Or try with <script>jfun("<?php echo $i;?>");</script>

share|improve this answer
up vote 0 down vote

Write the code before the PHP code. In that case the function jfun is known.

share|improve this answer

Your Answer

 
discard

By posting your answer, you agree to the privacy policy and terms of service.

Not the answer you're looking for? Browse other questions tagged or ask your own question.