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Is there a way to check if an array index exists or is null? isset() doesn't tell you whether the index doesn't exist or exists but is null. If I do : isset($array[$index]) || is_null($array[$index]) it won't work because if the index doesn't exist is_null will crash.

How can I check this please? Also is there a way to check only if something exist, no matter if it is set to null or not?

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Try !empty to check. – Devang Rathod Mar 9 at 11:45
Wouldn't the same if statements in a nested if structure work fine? – Chris Mar 9 at 11:46
"array_key_exists can surely do the trick." that is the answer..good.. +1 for u – Dipesh Parmar Mar 9 at 11:46
You should answer this question and then mark it as solved. Otherwise it'll always look like an open question. – Colin Morelli Mar 9 at 11:57
Can't accept my own answer before two days ^^ – Virus721 Mar 9 at 12:04
up vote 2 down vote

This is the very good question and you can use get_defined_vars() for this:

$foo = NULL;
$a = get_defined_vars();

if (array_key_exists('def', $a)) {
   // Should evaluate to FALSE
 }; 

if (array_key_exists('foo', $a)) {
   // Should evaluate to TRUE
};

This will solve your problem

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Ok but add the array_key_exist thing in it then – Virus721 Mar 9 at 12:20
up vote 2 down vote accepted

The function array_key_exists() can do that, and property_exists() for objects, plus what Vineet1982 said. Thanks for your help.

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