std::move
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Defined in header <algorithm>
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template< class InputIt, class OutputIt > OutputIt move( InputIt first, InputIt last, OutputIt d_first ); |
(C + + 11以来) | |
[first, last)
で別の範囲の先頭に、範囲d_first
内の要素を移動します。この操作の後に移動し、範囲内の要素は、依然として適切な型の有効な値が含まれていますが、移動前と同じ値であるとは限らないでしょう.[first, last)
, to another range beginning at d_first
. After this operation the elements in the moved-from range will still contain valid values of the appropriate type, but not necessarily the same values as before the move.You can help to correct and verify the translation. Click here for instructions.
目次 |
[編集] パラメータ
first, last | - | 移動する要素の範囲
Original: the range of elements to move The text has been machine-translated via Google Translate. You can help to correct and verify the translation. Click here for instructions. |
d_first | - | 目的の範囲の始まり。 d_first が[first, last) 内であれば、std::move_backwardはNJのstd ::移動</ span>をの代わりに使用する必要があります. Original: the beginning of the destination range. If d_first is within [first, last) , std::move_backward must be used instead of NJのstd ::移動</ span>を. </div>The text has been machine-translated via Google Translate. </div></div></div></div>
You can help to correct and verify the translation. Click here for instructions. |
Type requirements | ||
-InputIt must meet the requirements of InputIterator .
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-OutputIt must meet the requirements of OutputIterator .
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[編集] 値を返します
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[編集] 複雑
last - first
割り当てを移動.last - first
move assignments.You can help to correct and verify the translation. Click here for instructions.
[編集] 可能な実装
template<class InputIt, class OutputIt> OutputIt move(InputIt first, InputIt last, OutputIt d_first) { while (first != last) { *d_first++ = std::move(*first++); } return d_first; } |
[編集] 例
次のコードは、別のコンテナからスレッドオブジェクトを(それ自体がコピーではない)に移動します</ p>
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#include <iostream>
#include <vector>
#include <list>
#include <iterator>
#include <thread>
#include <chrono>
void f(int n)
{
std::this_thread::sleep_for(std::chrono::seconds(n));
std::cout << "thread " << n << " ended" << '\n';
}
int main()
{
std::vector<std::thread> v;
v.emplace_back(f, 1);
v.emplace_back(f, 2);
v.emplace_back(f, 3);
std::list<std::thread> l;
// copy() would not compile, because std::thread is noncopyable
のstd ::移動</ span>を(v.begin(), v.end(), std::back_inserter(l));
for(auto& t : l) t.join();
}
</div>
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thread 1 ended thread 2 ended thread 3 ended
[編集] も参照してください
(C++11) |
下位の順序で新しい場所に要素の範囲を移動します Original: moves a range of elements to a new location in backwards order The text has been machine-translated via Google Translate. You can help to correct and verify the translation. Click here for instructions. (関数テンプレート) |