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up vote 3 down vote favorite

I'm currently trying to use array_diff to remove 1 value from an array.

The code looks like this right now:

$item_id = 501;
$array = array_diff($user_items, array($item_id));

user items array: 501,501,502,502

results correctly in array: 502,502

Is it possible to remove only 1x501 instead of 2x501 value? or said differently: limit the removal by 1 value

array is then: 501,502,502

Any advice is appreciated

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2 Answers

up vote 2 down vote accepted

How about searching for the item, then removing it if it exists?

$key = array_search($item_id, $user_items)
if ($key !== FALSE) {
  unset($user_items[$key]);
}

Using unset isn't quite as straightforward as you'd think. See Stefan Gehrig's answer in this similar question for details.

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thanks this worked! –  Maarten Hartman Jan 30 at 23:42
up vote 5 down vote

You can use array_search to find and remove the first value:

$pos = array_search($item_id, $user_items);

if($pos !== false)
  unset($user_items[$pos]);
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And you can throw it in a loop: pastebin.com/xF2hhDnS –  Elliot B. Jan 30 at 23:18
 
The OP wanted to remove one value only. If he wants them all out, then array_diff would be a better choice –  onetrickpony Jan 30 at 23:20
 
That is what my code does. Take another look or try running it and output the results. –  Elliot B. Jan 30 at 23:56
 
Yes, I see now that you're iterating the needles. Still, only one replacement is needed in this case, so there's no point in using a loop –  onetrickpony Jan 30 at 23:59

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