sending array from javascript through url in php page but

The only way to send data to another page without showing them in the url is to use POST.

Basically, you can put your data into an invisible form input :

<form method="post" id="form" action="booking_status.php">
    <input name="array" id="array" type="hidden" value="" />
</form>
<a href="" onclick="sendForm(); return false;">Send</a>
<script type="text/javascript">
    function sendForm(){
        document.getElementById('array').value = JSON.stringify(rooms);
        document.getElementByid('form').submit();
    }
</script>

You can use a hidden form and the post method. Then you would use $_POST instead of $_GET.

<form action="script.php" onsubmit="this.firstChild.value=JSON.stringify(value);">
    <input type="hidden" value="" />
    <a href="javascript:this.form.submit();">Link text</a>
</form>

You can use a POST request, however this would require generating and submitting a form:

// assuming `rooms` already defined
var frm = document.createElement('form'), inp = document.createElement('input');
frm.action = "booking_status.php";
frm.method = "post";
inp.type = "hidden";
inp.name = "array";
inp.value = JSON.stringify(rooms);
frm.appendChild(inp);
document.body.appendChild(frm);
frm.submit();

Why not just POST the data instead then?

For example, with jQuery:

$.ajax({
  type: "POST",
  url: "booking_status.php",
  data: JSON.stringify(rooms),
  success: // add success function here!
});

The advantage is you're not passing some horrific URL. As an added bonus, this example is also asynchronous, so the user doesn't see any refresh in their browser.

Non-Framework Version

If you don't wish to use jQuery, you can do this with pure Javascript, using the XMLHttpRequest object, like so:

var url = "get_data.php";
var param = JSON.stringify(rooms);

var http = new XMLHttpRequest();
http.open("POST", url, true);


http.onreadystatechange = function() {//Call a function when the state changes.
    if(http.readyState == 4 && http.status == 200) {
    // Request has gone well. Add something here.
    }
}
http.send(param);