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I am having problems passing any kind of variable from PHP to JavaScript. Here is a simple example at jsFiddle. Why does it not return my string?

http://jsfiddle.net/funinabox/VkNe2/1/

<?php
//create php test string    
$teststring = "mystring"; 
?>


//Convert Php string to JavaScript string
var testvar = <?php echo $teststring; ?> ;
//Display output of the array elements;
alert(testvar);
share|improve this question
    
you are missing link –  Suresh Kamrushi Apr 22 '13 at 13:48
2  
you forgot the quotes: var testvar = "<?php echo $teststring; ?>"; –  x4rf41 Apr 22 '13 at 13:50
1  
You can't test PHP on jsfiddle. Uncaught SyntaxError: Unexpected token < –  jbabey Apr 22 '13 at 13:50
    
Look at the generated source code and you will be enlightened. (hopefully) –  SLaks Apr 22 '13 at 13:51
    
are you sure the php part comes before the <script> part? –  Aris Apr 22 '13 at 14:48
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4 Answers

up vote 4 down vote

You are missing "

var testvar = "<?php echo $teststring; ?>";

Here is a full example

<?php
//create php test string    
$teststring = "mystring"; 
?>


<html>
   <head>
   <script>
   //Convert Php string to JavaScript string
    var testvar = "<?php echo $teststring; ?>" ;
    //Display output of the array elements;
    alert(testvar);
    </script>
    </head>
<body></body>
</html>
share|improve this answer
    
Doesn't work. When I put it in quotes what I get back in the alert is the string <?php echo $teststring; ?> not mystring. –  user2301506 Apr 22 '13 at 14:29
    
@user2301506 I added an example demonstrating this. It does work. Are you sure, you are using <script> tags? –  DrColossos Apr 22 '13 at 14:33
    
Yes. I copy+pasted your code and all I get in the alert popup is the literal: <?php echo $teststring; ?> –  user2301506 Apr 22 '13 at 20:15
1  
If you get it literal, then there is no PHP environment running. You cannot run this from a file, you need to put it on a webserver that knows how to process PHP –  DrColossos Apr 23 '13 at 7:14
    
I also got literal when trying to shorthand a la "<? echo $var; ?>" at least when working locally with Xampp –  Helto Dec 23 '13 at 21:31
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up vote 0 down vote

try to do link below:

<?php
//create php test string    
$teststring = "mystring"; 
?>


//Convert Php string to JavaScript string
var testvar = '<?php echo $teststring; ?>' ;
//Display output of the array elements;
alert(testvar);
share|improve this answer
    
Doesn't work. When I put it in quotes (single or double) what I get back in the alert is the string <?php echo $teststring; ?> not mystring. –  user2301506 Apr 22 '13 at 14:30
add comment
up vote 0 down vote

My environment uses templates so this is not copy and paste code. However I was able to pass the variable to Javascript by doing this:

$teststring = 'mystring'; 

 $page_headers = <<<PAGEHEADERS
 <script>
    window.onload=function(){   
        var testvar = '$teststring';
        alert(testvar);
    };
</script>
PAGEHEADERS;

As long as the php variable is defined first you should be able to get a value from it simply by calling it.

share|improve this answer
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up vote 0 down vote

I reinstalled xampp and then made 1 change in c:\xampp\apache\conf\httpd.conf in the mime section section by adding (I did it in line 402 but anywhere in that section should be ok)... AddType application/x-httpd-php .html .htm

NOW IT WORKS!!!!!!!! This looks like a big mistake in the current xampp distribution for Win 7 32-bit.

share|improve this answer
    
This is not a mistake in XAMPP: by default, .html files are not passed through the PHP engine, as this would slow them down unnecessarily. In general, if you are writing new PHP pages, give them a .php suffix instead. –  halfer Apr 27 '13 at 11:03
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