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How can i add php content or php variable inside Java-script alert box?! I tried to make it work few ways but it is only popping up a blank box rather than the contents of php variable.

Here is the code: 

<script language="javascript">
    $(document).ready(function() {
        $("#a").blur(function() {           
            <?php $b = $_POST['a'];

            if(isset($_POST['update'])) {
            mysql_query("UPDATE tbl_travel set fld_a='".$_POST[$b]."' where fld_id = '".$_POST["id"]."' ") or die(mysql_error());
            } ?>

                alert (<?php $b ?>);
           });
    });
</script>

Thank You for your Help :)

share|improve this question
1  
alert(<?php print($b); ?>); will do –  Shankar Damodaran Sep 7 at 10:00
 
Thanks shankar..it works very well :) –  Pooja Sep 7 at 10:11
 
Cool.Yw. Happy Coding ! –  Shankar Damodaran Sep 7 at 10:12
1  
Yeah Done. ^_^. –  Shankar Damodaran Sep 7 at 10:18
 
possible duplicate of Passing a PHP variable to JavaScript –  M Khalid Junaid Sep 7 at 10:21
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2 Answers

up vote 2 down vote accepted

Change this

alert (<?php $b ?>);

to this

alert ('<?php echo $b; ?>');

You need to output the value of $b and add quotes inside the alert.

About PHP - echo

share|improve this answer
 
Hey thanks for the answer totally missed using echo before $b. BTW need to put double quotes too alert ("<?php echo $b; ?>"); –  Pooja Sep 7 at 10:05
1  
You don't need low reputation to accept answer, just to upvote. You get also +2 when you accept. :) –  Sergio Sep 7 at 10:21
1  
@Pooja, under the score of the answer were you can upvote and downvote there is a check mark, press there in the answer you want to accept and you get +2 reputation. You have some other old questions you asked were you can do that also :) –  Sergio Sep 7 at 10:28
1  
@Pooja, exactly! if you do that on your other questions you will get more reputation also –  Sergio Sep 7 at 10:30
1  
oh yes i found it! Thanks for informing about that...accepted your answer ^_^ –  Pooja Sep 7 at 10:31
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up vote 1 down vote

Have you tried this?

alert ('<?php echo $b ?>');
share|improve this answer
 
yes it works very well thank you :) –  Pooja Sep 7 at 10:29
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