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I've found at the StackOverflow answer here exactly how I want to post data to another web url.

However, I want this command to be executed in my php web script, not from the terminal. From looking at the curl documentation, I think it should be something along the lines of: 

<?php 

$url = "http://myurl.com";
$myjson = "{"column1":"1","colum2":"2","column3":"3","column4":"4","column5":"5","column6":"6"}";
$ch = curl_init();
curl_setopt($ch, CURLOPT_URL, $url);
curl_setopt($ch, CURLOPT_POST, TRUE);
curl_setopt($ch, CURLOPT_POSTFIELDS, $myjson);
curl_close($ch);

?>

What is the best way to do that?

The current terminal command that is working is:

curl -X POST -H "Content-Type: application/json" -d '{"column1":"1","colum2":"2","column3":"3","column4":"4","column5":"5","column6":"6"}' https://myurl.com
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3  
Did you run this code? Short of improper strings, you're on the right track. –  Jason McCreary Jul 22 '13 at 14:41
    
I did, just to be sure. It isn't accessing the url, while my terminal command is working (which I added to question). –  AllieCat Jul 22 '13 at 14:44
    
Well, $myjson is not set correct... change the first and last " for ' ;) (quote it correctly!) –  Eleazan Jul 22 '13 at 14:46
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1 Answer

up vote 1 down vote accepted

There are two problems:

  1. You need to properly quote $myjson. Read the difference between single and double quoted strings in PHP.
  2. You are not sending the curl request: curl_exec()

This should move you in the right direction:

<?php
$url = 'http://myurl.com';
$myjson = '{"column1":"1","colum2":"2","column3":"3","column4":"4","column5":"5","column6":"6"}';
$ch = curl_init();
curl_setopt($ch, CURLOPT_URL, $url);
curl_setopt($ch, CURLOPT_POST, TRUE);
curl_setopt($ch, CURLOPT_POSTFIELDS, $myjson);
$result = curl_exec($ch);
curl_close($ch);
share|improve this answer
    
Thank you so much for the help. I can't believe I forgot that! :) –  AllieCat Jul 22 '13 at 17:19
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