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up vote 0 down vote favorite

I am trying to loop through an array with duplicate indexes. But it only prints 3 times not all of them. I want to print all values in the array is that possible?

Here is my PHP code:

$data['Video'][0]['name']='a';
$data['Video'][1]['name']='b';
$data['Video'][1]['name']='c';
$data['Video'][3]['name']='d';
$data['Video'][3]['name']='e';

foreach ($data['Video'] as $video) {
    print_r($video);
}

And here is the output of that code:

Array
(
    [name] => a
)
Array
(
    [name] => c
)
Array
(
    [name] => e
)
share|improve this question
    
You are changing the value of array index 3 and 1 two times. So in total there are only 3 arrays in $data['Video'] –  Subin Dec 25 '13 at 6:21
    
it will overwrite the value at that index... –  Pranav C Balan Dec 25 '13 at 6:25
add comment

2 Answers

up vote 0 down vote accepted

Please avoid duplicate entry of keys otherwise try this,

  $data['Video'][]['name']='a';
  $data['Video'][]['name']='b';
  $data['Video'][]['name']='c';
  $data['Video'][]['name']='d';
  $data['Video'][]['name']='e';

  foreach ($data['Video'] as $video) {
      print_r($video);
  }
share|improve this answer
    
It solved my problem. thanks –  Abhijeet Kambli Dec 25 '13 at 6:30
add comment
up vote 1 down vote

Well, the duplicate indexes negate each other. So this is expected behavior. So when you set this in your code:

$data['Video'][0]['name']='a';
$data['Video'][1]['name']='b';
$data['Video'][1]['name']='c';
$data['Video'][3]['name']='d';
$data['Video'][3]['name']='e';

It really just means this:

$data['Video'][0]['name']='a';
$data['Video'][1]['name']='c';
$data['Video'][3]['name']='e';

The newer data assigned to the keys 1 and 3 overwrite what was previously there.

share|improve this answer
    
nice explainment +1 but they dont "negate" in mine opinion an better definition would be "overwrite" or "override" –  Raymond Nijland Dec 25 '13 at 16:05
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