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up vote 5 down vote favorite

This question already has an answer here:

I have an array of objects that looks like the following:

            {value: 20, color: 'F88C00'},
            {value: 40, color: 'D8605F'},
            {value: 20, color: '72C380'},
            {value: 20, color: '2C7282'},
            {value: 20, color: '72C380'}

I want to use javascript/jquery to loop through them to check if there are any duplicates in the color column, and if there are duplicates, here '72C380' occurs twice. Then there should be only one entry but their values should be summed.

Desired Output:

            {value: 20, color: 'F88C00'},
            {value: 40, color: 'D8605F'},
            **{value: 40, color: '72C380'},**
            {value: 20, color: '2C7282'}

I know how to do that in python, but not JS

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marked as duplicate by Dalorzo, Bhushan Kawadkar, cookie monster, Code Lღver, Huangism Jun 18 at 14:33

This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.
    
Do you want to delete it? –  Kermani Jun 18 at 5:32
    
I want to delete the duplicate ones but add upp the values –  Rahul Bhatia Jun 18 at 5:39

2 Answers 2

up vote 7 down vote

You can use a temp map like this

var array = [{
    value: 20,
    color: 'F88C00'
}, {
    value: 40,
    color: 'D8605F'
}, {
    value: 20,
    color: '72C380'
}, {
    value: 20,
    color: '2C7282'
}, {
    value: 20,
    color: '72C380'
}];

var op = [],
    map = {}, it, item;
for (var i = 0; i < array.length; i++) {
    it = array[i];
    item = map[it.color];
    if (item) {
        item.value += it.value;
    } else {
        map[it.color] = item = {
            value: it.value,
            color: it.color
        };
        op.push(item);
    }
}
console.log(op)

Demo: Fiddle

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up vote 0 down vote

console it ...

var collection = [{value: 20, color: 'F88C00'},
            {value: 40, color: 'D8605F'},
            {value: 20, color: '72C380'},
            {value: 20, color: '2C7282'},
            {value: 20, color: '72C380'}];


var colors = [];
var result = collection;
$.each(result, function(i, item){ 
  if(colors.indexOf(item.color)!= -1){ 
      $.each(result,function(f, find){
        if(find.color == item.color){
          result[f].value += item.value;
        }
      })
      delete result[i];
  }else{
     colors.push(item.color);  
  } 
})
var colors = [];
console.log(result);
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