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up vote -2 down vote favorite

I have an array like this

[
     ["Adrian Garcia", "42"],
     ["Alberto Guglielmi", "42"],
     ["Alice Fung Yee Ng", "15"],
     ["Christopher Wilson", "4"],
     ["Claudio Meneghetti", "13"],
     ["Bahadir Tanriover", "15"],
     ["Baitinger Martin", "36"],
     ["Bill Cash", "15"],
     ["Brian Kuhlmann", "15"],
     ["Caesar Lima", "15"],
     ["Carl Tremblay", "42"],
     ["Aorta", "42"],
     ["Charles Harris", "15"],
     ["Chet Morrison", "15"],
     ["Chico Audi", "11"],
     ["Andreas Gemperle", "42"],
     ["Angel Burns", "42"],
     ["Arno Bosma", "42"],
     ["Chris Bailey", "15"],
     ["Chris Close", "1"],
     ["Christoph Martin Schmid", "42"],
     ["Ben Isselstein", "25"],
     ["Colin Thomas", "15"],
     ["Craig Cameron Olsen", "42"],
     ["Craig Easton", "42"]
]

I need to sort this array by numbers and also the name in ascending order. I find most of the solutions for sort by single value. But I need to sort by two values.

I need output like below.

[
    ["Chris Close", "1"]
    ["Christopher Wilson", "4"]
    ["Chico Audi", "11"]
    ["Claudio Meneghetti", "13"]
    ["Alice Fung Yee Ng", "15"]
    ["Bahadir Tanriover", "15"]
    ["Bill Cash", "15"]
    ["Brian Kuhlmann", "15"]
    ["Caesar Lima", "15"]
    ["Charles Harris", "15"]
    ["Chet Morrison", "15"]
    ["Chris Bailey", "15"]
    ["Colin Thomas", "15"]
    ["Ben Isselstein", "25"]
    ["Baitinger Martin", "36"]
    ["Adrian Garcia", "42"]
    ["Alberto Guglielmi", "42"]
    ["Carl Tremblay", "42"]
    ["Aorta", "42"]
    ["Andreas Gemperle", "42"]
    ["Angel Burns", "42"]
    ["Arno Bosma", "42"]
    ["Christoph Martin Schmid", "42"]
    ["Craig Cameron Olsen", "42"]
    ["Craig Easton", "42"]
]
share|improve this question
1  
I tried most of the solutions -- Show us what you tried. –  George Aug 13 at 9:50
    
All that solutions are sort with only single value. Ex: myArray.sort(function(a, b) { return a[1] - b[1]; }); –  RajivRisi Aug 13 at 9:53
    
@RajivRisi so you can use not single value in sort function :-) –  Grundy Aug 13 at 9:53
1  
OP, this has nothing to do with jQuery. Just plain JavaScript. –  putvande Aug 13 at 9:57
1  
Can you show what the output should look like? –  putvande Aug 13 at 10:09

3 Answers 3

up vote 1 down vote accepted

A shorter version would be just to use JavaScripts own sort function:

// First sort on number (second column)
array.sort(function(a, b) { return a[1] - b[1] });
// Then sort on name (first column)
array.sort(function(a, b) { return a[0] - b[0] });

which outputs as

[
    ["Chris Close", "1"],
    ["Christopher Wilson", "4"],
    ["Chico Audi", "11"],
    ["Claudio Meneghetti", "13"],
    ["Alice Fung Yee Ng", "15"],
    ["Bahadir Tanriover", "15"],
    ["Bill Cash", "15"],
    ["Brian Kuhlmann", "15"],
    ["Caesar Lima", "15"],
    ["Charles Harris", "15"],
    ["Chet Morrison", "15"],
    ["Chris Bailey", "15"],
    ["Colin Thomas", "15"],
    ["Ben Isselstein", "25"],
    ["Baitinger Martin", "36"],
    ["Adrian Garcia", "42"],
    ["Alberto Guglielmi", "42"],
    ["Carl Tremblay", "42"],
    ["Aorta", "42"],
    ["Andreas Gemperle", "42"],
    ["Angel Burns", "42"],
    ["Arno Bosma", "42"],
    ["Christoph Martin Schmid", "42"],
    ["Craig Cameron Olsen", "42"],
    ["Craig Easton", "42"]
]

Fiddle

share|improve this answer
up vote 2 down vote

try something like this: 

   $(array).sort(function(first, second){
       if(first[0] < second[0]){return -1;}
       else if(first[0] > second[0]){return 1;}
       else if(first[0] === second[0]){
          if(parseInt(first[1]) < parseInt(second[1])){return -1;}
          else return 1;
       }
    });

DEMO

if you vant to sort by number first, use this:

   $(array).sort(function(first, second){
       if(parseInt(first[1]) < parseInt(second[1])){return -1;}
       else if(parseInt(first[1]) > parseInt(second[1])){return 1;}
       else if(parseInt(first[1]) === parseInt(second[1])){
          if(first[0] < second[0]){return -1;}
          else return 1;
       }
    });
share|improve this answer
    
Because this is only sorting it by name (first column). –  putvande Aug 13 at 10:00
    
are you sure. look at 3 else if –  Aleksei Bulgak Aug 13 at 10:01
    
@putvande, firstly it sort using name and if only if name is the same it sort by value –  Aleksei Bulgak Aug 13 at 10:02
    
Did you try it yourself? The name will never be the same so you will never get in that last else if statement. –  putvande Aug 13 at 10:02
    
@putvande, yes. look this –  Aleksei Bulgak Aug 13 at 10:04
up vote -1 down vote

I sorted by number

DEMO

 var arr=[
    ["Adrian Garcia", 42],
    ["Alberto Guglielmi", 42],
    ["Alice Fung Yee Ng", 15],
    ["Christopher Wilson",4],
    ["Claudio Meneghetti", 13],
    ["Bahadir Tanriover", 15],
    ["Baitinger Martin", 36],
    ["Bill Cash", 15],
    ["Brian Kuhlmann", 15],
    ["Caesar Lima", 15],
    ["Carl Tremblay", 42],
    ["Aorta", 42],
    ["Charles Harris", 15],
    ["Chet Morrison", 15],
    ["Chico Audi",11],
    ["Andreas Gemperle", 42],
    ["Angel Burns", 42],
    ["Arno Bosma", 42],
    ["Chris Bailey", 15],
    ["Chris Close", 1],
    ["Christoph Martin Schmid", 42],
    ["Ben Isselstein", 25],
    ["Colin Thomas", 15],
    ["Craig Cameron Olsen", 42],
    ["Craig Easton", 42]
]

for (var i = 0; i < arr.length; i++) {// No of times loop executed for given array

    for (var j = 0; j < (arr.length - i) - 1; j++) {   //  it wil save the one value each iteration  

        if (arr[j][1] > arr[j + 1][1]) {
            var temp = arr[j + 1];
            arr[j + 1] = arr[j];
            arr[j] = temp;
        }


    }

}
alert(arr);
share|improve this answer
    
That is half of the answer. –  putvande Aug 13 at 9:57
    
you sort by string not a number –  Grundy Aug 13 at 9:58
    
@Grundy did you debug that code.i am using number not string –  Bala Aug 13 at 10:01
    
i mean that you have as result 1, 11,13 ... instead of 1,4... –  Grundy Aug 13 at 10:02
    
@Grundy ya ,there is one mistake numbers also string changed to number ["Christopher Wilson",4], –  Bala Aug 13 at 10:10

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