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up vote 0 down vote favorite 
$useridtofind= 123;

$users=array();

while ($data = mysql_fetch_array ($result))
{

        $userid = $data['userid'];
    $age = $data['age'];
    $gender = $data['gender'];
    $dob = $data['dob'];

    $users[$userid] => array(
        'age'=> $age, 
        'gender'=> $gender, 
        'dob' => $dob
        )
}


$useridtofind=123;

for($v=0; $v< count($users); $v++)
{
    if($users[$v]== $useridtofind)
    {
        //how to go with grab value of age, gender, dob  here?      
    }
}
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2 Answers 2

up vote 0 down vote accepted

You seem to be using the user id as the index of the user in the array. If this is the case, you shouldn't be using a for loop, you should just check if the key exists within the array:

$useridtofind = 123;

if (array_key_exists($useridtofind, $users)) {
  $user = $users[$useridtofind];

  echo "User exists: ", $user['age'], '/', $user['gender'], '/', $user['dob'];
} else {
  echo "User doesn't exist";
}
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up vote 2 down vote

You already use the id to index the array.

Just use:

if (isset($users[$usertofind])) {
  $user = $users[$usertofind]; 
  echo $user['age'];
  echo $user['dob'];
  echo $user['gender'];
}

EDIT: Added isset check and reduced the number of times referencing the same array element

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