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up vote -2 down vote favorite

I have an array like this:

$mainMenu[0][0] = "index.php?prod=0";
$mainMenu[0][1] = "Product One";
$mainMenu[1][0] = "index.php?prod=1";
$mainMenu[1][1] = "Product Two";
$mainMenu[2][0] = "index.php?prod=2";
$mainMenu[2][1] = "Product One";

In the first index I save the url of the link. In the second is the text, that should be displayed. How can I run a loop (and what loop should I run) to print the menu?

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5  
what have you tried, what was the actual problem? doesn't seem too hard - for/foreach loop is probably the weapon of choice... –  codeling Dec 15 '11 at 23:28

2 Answers 2

up vote 1 down vote

It's a simpe loop and print statement:

foreach ($mainMenu as $entry) {
    list($link, $title) = $entry;
    print <<< HTML
        <a href="$link">$title</a>
HTML;
}

Or something like that.

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up vote 1 down vote 
$menu='';
foreach($mainMenu as $menuItem){
    $menu.='<a href="'.$menuItem[0].'">'.$menuItem[1].'</a>';
}
return $menu;

EDIT: ...or use the list() method as @mario suggests. Both should work.

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