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up vote -3 down vote favorite

I have two cases

  1. Input-> 3,4,1

Get last value into a vector. so Vector cls contains 1. So for further processing I am converting it to integer

int c = Integer.parseInt(cls.get(0));

this works fine But for 2 nd case it fails.

  1. 3.0,4.0,1.0

Vector cls contains 1.0 and while converting to int it fails with NumberFormatException

int c= Integer.parseInt(cls.get(0));

Caused by: java.lang.NumberFormatException: For input string: "1.0" at java.lang.NumberFormatException.forInputString(NumberFormatException.java:65)

What can I do as a workaround by keeping Vector as String itself. Edit I need to work my code for both the cases.

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9  
an Integer is not a decimal type. When you have decimals, try with Double or Float instead. – Stultuske Jun 30 '15 at 10:15
1  
its a double so you have to use double d = Double.parseDouble(cls.get(0)); int i = (int) d; – Karthigeyan Jun 30 '15 at 10:17
    
How can I work for both cases? – Unmesha SreeVeni Jun 30 '15 at 10:21
    
catch and try again for double/float... – Garry Jun 30 '15 at 10:24
up vote 5 down vote 
int c = 0;

try {

    c = Integer.parseInt(cls.get(0));

} catch(NumberFormatException e) {

    double d = Double.parseDouble(cls.get(0)); 

    c = (int) d;
}
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up vote 1 down vote 
int c=(int)Double.parseDouble(cls.get(0));
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up vote 0 down vote

you should use type float, like float c = Float.parseFloat(cls.get(0));

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Should be a comment – shapiro yaacov Jun 30 '15 at 14:54

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