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up vote 0 down vote favorite 
<?php
    include_once 'forecastVo.php';
    include_once 'BaseVo.php';
    $count=0;
    $json_url = file_get_contents(
        'http://maps.google.com/maps/api/geocode/json' .
        '?address='jaipur'&sensor=false');                //line 9
    if($json_url){
        $obj = json_decode($json_url,true);

        $obj2= $obj['results'];
    }
?>

I am getting an error:

Parse error: syntax error, unexpected T_STRING in /home/a4101275/public_html/index.php on line 9

line 9 is where I am using the file_get_contents.

What does the error mean and how do I fix it?

share|improve this question
    
You have to use your escape characters correctly. – Matt Aug 2 '12 at 20:12
    
You can get this error for many different reasons 1: forget a semicolon on a previous line, 2: forget a concatenation operator dot . between variables, or like in your case, 3: delimit a string using single quotes which contain single quotes. The interior single quotes are treated as delimiters and complete the string. The PHP parser sees the word after it as a syntax error. As matt said above, your interior single quotes need to be properly escaped with a \'in order to be interpreted as literals rather than delimiters. – Eric Leschinski Oct 27 at 20:17
up vote 3 down vote accepted

You have to use your escape characters correctly. You can't have a single-quote (') inside of a single-quote-encapsulated string. It breaks it. In order to continue the string and have PHP interpret your inner single-quote literally, you have to escape it with \.

$json_url = file_get_contents('http://maps.google.com/maps/api/geocode/json?address=\'jaipur\'&sensor=false');

Or you can use the alternative string encapsulator, double-quote (").

$json_url = file_get_contents("http://maps.google.com/maps/api/geocode/json?address='jaipur'&sensor=false");

For future reference, Parse error: syntax error, unexpected T_STRING usually means you have a bad string somewhere on that line.

share|improve this answer
up vote 1 down vote

Why quote it at all? I can't imagine the Google API requires (or even expects) that value to be quoted.

$json_url = file_get_contents('http://maps.google.com/maps/api/geocode/json?address=jaipur&sensor=false'); //line 9

Or, is jaipur a variable? If so:

$json_url = file_get_contents("http://maps.google.com/maps/api/geocode/json?address=$jaipur&sensor=false"); //line 9

Hard to tell from your question what it is you're trying to accomplish...

share|improve this answer
up vote 0 down vote 
$json_url = file_get_contents("http://maps.google.com/maps/api/geocode/json?address='jaipur'&sensor=false");

Or escaping it with \

share|improve this answer
    
thanks it works now – shiven Aug 2 '12 at 20:18

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