up vote 6 down vote favorite
1

Can I pass a variable number of arguments into a Javascript function? I have little knowledge in JS. I want to implement something like the following:

 function CalculateAB3(data, val1, val2, ...)
    {
        ...
    }
share|improve this question
    
yes you can :-) heres a good tutorial w3schools.com/js/js_functions.asp – Hellgorithm Oct 28 '13 at 7:18
    
Yes and eww.... – Paul Draper Oct 28 '13 at 7:19
3  
You can pass multiple arguments, but the better way is that you can pass an object or an array instead – AmGates Oct 28 '13 at 7:19
    
yes...you can pass any number of parameters...javascript.info/tutorial/arguments – shemy Oct 28 '13 at 7:19
    
Javascript supports passing of multiple parameters through function. – Jenz Oct 28 '13 at 7:20
up vote 11 down vote accepted

You can pass multiple parameters in your function and access them via arguments variable. Here is an example of function which returns the sum of all parameters you passed in it

var sum = function () {
    var res = 0;
    for (var i = 0; i < arguments.length; i++) {
        res += parseInt(arguments[i]);
    }
    return res;
 }

You can call it as follows:

sum(1, 2, 3); // returns 6
share|improve this answer
    
Please show the actual prototype. it gives syntax error. – Rajesh Paul Oct 28 '13 at 7:59
    
@RajeshPaul I updated function declaration. try again. – aga Oct 28 '13 at 8:22
up vote 3 down vote

Simple answer to your question, surely you can

But personally I would like to pass a object rather than n numbers of parameters

Example:

function CalculateAB3(obj)
{
    var var1= obj.var1 || 0; //if obj.var1 is null, 0 will be set to var1 
    //rest of parameters
}

Here || is logical operator for more info visit http://codepb.com/null-coalescing-operator-in-javascript/

A null coalescing operator for javascript? is a good read

share|improve this answer
up vote 0 down vote

Yes, you can make it. Use variable "arguments" like there:

function test() {
  for(var i=0; i<arguments.length; i++) {
    console.log(arguments[i])
  }
}
share|improve this answer

Your Answer

 
discard

By posting your answer, you agree to the privacy policy and terms of service.

Not the answer you're looking for? Browse other questions tagged or ask your own question.