std::is_partitioned
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Заголовочный файл <algorithm>
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template< class InputIt, class UnaryPredicate > bool is_partitioned( InputIt first, InputIt last, UnaryPredicate p ); |
(начиная с C++11) | |
Возврат true, если все элементы в диапазоне
[first, last)
, которые удовлетворяют предикату p
предстать перед всеми элементами, которые этого не делают. Также возвращает true если [first, last)
пусто.Original:
Returns true if all elements in the range
[first, last)
that satisfy the predicate p
appear before all elements that don't. Also returns true if [first, last)
is empty.The text has been machine-translated via Google Translate.
You can help to correct and verify the translation. Click here for instructions.
You can help to correct and verify the translation. Click here for instructions.
Содержание |
[править] Параметры
first, last | - | диапазон элементов для проверки
Original: the range of elements to check The text has been machine-translated via Google Translate. You can help to correct and verify the translation. Click here for instructions. | |||||||||
p | - | unary predicate which returns true для элементов, как ожидается, будет найден в начале диапазона . Original: for the elements expected to be found in the beginning of the range The text has been machine-translated via Google Translate. You can help to correct and verify the translation. Click here for instructions. The signature of the predicate function should be equivalent to the following:
The signature does not need to have const &, but the function must not modify the objects passed to it. | |||||||||
Type requirements | |||||||||||
-InputIt must meet the requirements of InputIterator .
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[править] Возвращаемое значение
true, если диапазон
[first, last)
пустой или разбивается p
. false иначе.Original:
true if the range
[first, last)
is empty or is partitioned by p
. false otherwise.The text has been machine-translated via Google Translate.
You can help to correct and verify the translation. Click here for instructions.
You can help to correct and verify the translation. Click here for instructions.
[править] Сложность
В большинстве
std::distance(first, last)
применения p
.Original:
At most
std::distance(first, last)
applications of p
.The text has been machine-translated via Google Translate.
You can help to correct and verify the translation. Click here for instructions.
You can help to correct and verify the translation. Click here for instructions.
[править] Возможная реализация
template< class InputIt, class UnaryPredicate > bool is_partitioned(InputIt first, InputIt last, UnaryPredicate p) { for (; first != last; ++first) if (!p(*first)) break; for (; first != last; ++first) if (p(*first)) return false; return true; } |
[править] Пример
#include <algorithm> #include <array> #include <iostream> int main() { std::array<int, 9> v = { 1, 2, 3, 4, 5, 6, 7, 8, 9 }; auto is_even = [](int i){ return i % 2 == 0; }; std::cout.setf(std::ios_base::boolalpha); std::cout << std::is_partitioned(v.begin(), v.end(), is_even) << ' '; std::partition(v.begin(), v.end(), is_even); std::cout << std::is_partitioned(v.begin(), v.end(), is_even) << ' '; std::reverse(v.begin(), v.end()); std::cout << std::is_partitioned(v.begin(), v.end(), is_even); }
Вывод:
false true false
[править] См. также
делит диапазон элементов на две группы Original: divides a range of elements into two groups The text has been machine-translated via Google Translate. You can help to correct and verify the translation. Click here for instructions. (шаблон функции) | |
(C++11) |
locates the partition point of a partitioned range (шаблон функции) |